calculating approximated MOE's for summed estimates that =0

I am working on calculating approximated MOE's for summed estimates in ACS data. I understand that when at least one estimate 0, the MOE calculation should use only the largest MOE value for the estimates that equal zero (slide 26, https://www.census.gov/content/dam/Census/programs-surveys/acs/guidance/training-presentations/2016_MOE_Slides_01.pdf). Does anyone have experience with programming this rule into SAS (or Stata)?

Thoughts/guidance would be most appreciated.

 

Best,

Miriam

  • Miriam Please contact me directly andy@socialexplorer.com
  • Piece of cake:

    clear
    * fake data
    input id group estimate moe
    101 1 36 56
    102 1 0 25
    103 1 0 28
    104 1 0 31
    201 2 0 24
    202 2 58 62
    301 3 0 27
    302 3 0 19
    303 3 0 22
    401 4 0 27
    501 5 73 49
    502 5 22 26
    601 6 48 37
    end
    * groups 1 and 2 are generic cases of mixed zero and nonzero estimates
    * group 3 is all zeroes -- expect MOE = 27
    * groups 4 and 6 have only one case -- expect MOE to roll over
    * group 5 is a generic case with all nonzeroes
    list, sepby(group)

    egen tot_est = sum(estimate), by(group)
    * sum the MOEs for nonzero estimates
    egen sum_moe_sq = sum( moe*moe*(estimate>0) ), by(group)
    list, sepby(group)

    * isolate out the zero estimate with the largest MOE
    bysort group estimate (moe) : replace sum_moe_sq = sum_moe_sq + moe*moe*(estimate==0)*(_n==_N)
    list, sepby(group)

    * propagate the largest sum_moe_sq to the whole group
    * if there were no nonzero estimates, as in group 5, this is innocuous -- no changes are made
    * if there were any nonzero estimates, the sum of squared MOEs was modified once
    * by the largest MOE^2 of the nonzero estimates, and that's the MOE to use
    bysort group (sum_moe_sq) : replace sum_moe_sq = sum_moe_sq[_N]
    list, sepby(group)

    * take the square roots
    gen tot_moe = sqrt(sum_moe_sq)
    list, sepby(group)

    * c.f. target MOEs where nontrivial
    di sqrt(56*56+31*31)
    di sqrt(62*62+24*24)
    di sqrt(49*49+26*26)

    This of course can be wrapped into a program, or even into an -egen- command. And a Stata Tip should be published in Stata Journal on this :).